1. If a chemical reaction is elementary, the exponents in its equilibrium constant expression will __________ agree with (match) the coefficients in the balanced equation.

a) always | b) sometimes | c) never |

a) always | b) sometimes | c) never |

a) the numerical value of its equilibrium constant (K

b) the numerical value of its equilibrium constant (K

c) the numerical value of its equilibrium constant (K

d) the numerical value of its equilibrium constant (K

4. A chemical equilibrium favors the products if

a) the numerical value of its equilibrium constant (K

b) the numerical value of its equilibrium constant (K

c) the numerical value of its equilibrium constant (K

d) the numerical value of its equilibrium constant (K

5. At 25

2SO

has the equilibrium constant K

a) Almost all of the SO

b) Very little SO

c) An equal number of moles of SO

d) The compostion of the equilibrium mixture can not be determined, because the position of a chemical equilibrium is not related to the size of the equilibrium constant.

6. At 25

2HF(g) <----------> H

has the equilibrium constant K

a) Almost all of the original HF would still be in the reaction vessel. Only trace amounts of H

b) Only trace amounts of HF would remain in the vessel. Almost all of it would have decomposed to produce H

c) There would be an equal number of moles of HF, H

d) The compostion of the equilibrium mixture can not be determined, because the position of a chemical equilibrium is not related to the size of the equilibrium constant.

7. At high temperatures, hydrogen iodide (HI) decomposes into the elements hydrogen (H

2HI(g) <----------> H

The concentration of each gas in the equilibrium mixture was determined and the results were as follows:

[HI]_{eq} = 0.3750 M |
[H_{2}]_{eq} = 0.0813 M |
[I_{2}]_{eq} = 0.0344 M |

a) 1.06 x 10^{-3} |
b) 1.99 x 10^{-2} |
c) 50.3 |

d) 134 | e) 953 |

CO(g) + 3H

In an experiment, a chemist put 0.1000 moles of CO and 0.3000 moles of H

a) 0.133 | b) 0.255 | c) 0.734 | d) 1.36 | e) 3.93 |

N

At 2127

[N_{2}]_{eq} = 0.058 M |
[O_{2}]_{eq} = 0.027 M |

a) 3.9 x 10^{-6} M |
b) 2.0 x 10^{-3} M |
c) 6.5 x 10^{-3} M |

d) 4.1 x 10^{-2} M |
e) 3.8 x 10^{-1} M |

2SO

has the equilibrium constant K

[SO_{2}]_{initial} = 1.45 M |
[O_{2}]_{initial} = 2.83 M |
[SO_{3}]_{initial} = 0.11 M |

a) There will be reaction from left to right. (Net conversion of SO

b) There will be reaction from right to left. (Net conversion of SO

ANSWERS:

1) a 2) a 3) b 4) a 5) b

6) a 7) b 8) e 9) b 10) a